Find the value of a so that the system has no solutions.
y = 11x + 14
2y - 4 = ax + 3y
Find the value of a.
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\(y = 11x + 14\\ \underline{2y - 4 = ax + 3y}\\ 3y-4=(11+a)x+14+3y\\ (11+a)x+18=0\\x=- \dfrac{18}{\color{blue}11+a}\)
If a = -11 then so that the system has no solutions.
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