For a certain value of the system
3a + 4b = 7
6a + 4b = k - 4b + 2a
has infinitely many solutions What is k?
Here's a start...
In the equation 3a + 4b = 7, you can multiply through by 3 to get 9a + 12b = 21.
Next, in the equation 6a + 4b = k - 3a - 8b you can start by simplifying to 4a + 8b = k.
