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Hi, can you please help me solve the simultanious equation with the steps of how to do it.

 

a^2 + b^2 = 25

3a + b = 5

 Oct 11, 2020
 #1
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The second equation shows b = 5-3a       put this into the first equation for b

 

a^2   + (5-3a)^2 = 25    expand

a^2   + 9a^2 -30a + 25 = 25   

10a^2 -30a         =0

a(10a-30) = 0

a = 0     and   3          then b =   5   and   -4     corrrespondingly  

 Oct 11, 2020

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