Im having trouble with this
One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab = 72. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab = 72. What is the value of b in this ordered pair?
To find b, consider ab4 = 48
We will divide both sides by ab.
Since ab=72, we will divide the left side
by "ab" and the right side by its equal 72.
ab4 48
—— = ——
ab 72
Note that ab4 = (ab) * (b3)
Cancel ab out of the left side.
Reduce 48/72 on the right side.
b3 2
—— = ——
1 3
b = cube root of (2 / 3)
.
