Find the ordered pair, (s, t) that satisfies the system
(s/2) - 3t = -1,
3t - 2s = 3 + s
Find (s, t).
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\(\dfrac{s}{2} - 3t = -1\ |\ \cdot 2\\ s-6t=-2\ |\ -s\\ -6t=-s-2\\ 3t - 2s = 3 + s\ |\ \cdot -2\\ -6t+4s=-6-2s\ |\ -4s\\ -6t=-6s-6\\ -s-2=-6s-6\\ 5s=-4\\ \color{blue}s=-0,8\)
\(-6t=-6s-6\ |\ \div -6\\ t=s+1\\ t=-0.8+1\\ \color{blue}t=0.2\)
\(\)
The ordered pair \(\color{blue}(s,t)=(-0.8,\ 0.2).\)
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