To find the ordered triple (p,q,r), we can use substitution:
First equation: 2q=−p ---> q=−p/2
Second equation: −p/2−2r=0 ---> −p/2=2r ---> p=−4r
Third equation: −4r+r=5 ---> −3r=5 ---> r=−5/3
Plugging in -5/3 for r: q+10/3=0 ---> q=−10/3
Plugging in -10/3 for q: p−20/3=0 ---> p=20/3
the ordered triple (p,q,r) is ( 20/3 , -10/3 , -5/3 )
Answer: ( 20/3 , -10/3 , -5/3 )