Solve the system of equations:
3a+b+c+d+e+f=43
a+3b+c+d+e+f=51
a+b+3c+d+e+f=67
a+b+c+3d+e+f=32
a+b+c+d+3e+f=81
a+b+c+d+e+3f=52
Using Wolfram Alpha, we get a = -104/253, b = 2080/253, c = 2496/253, d = 3328/253, e = 1508/253, f = 4056/253
You can solve this without WolframAlpha. Start by adding all the equations together:
4a + 4b + 4c + 4d + 4e + 4f = 326
a + b + c + d + e + f = 81.5
If each equation is called (1), (2), (3), ..., etc, then you can subtract our "master equation" from each like so:
3a + b + c + d + e + f = 43
a + b + c + d + e + f = 81.5
Subtract, so 2a = -38.5 and a = -19.25.
The numbers may be incorrect, but you get the idea.