Find the value of a so that the system has no solutions.
y = 11x + 14
2x - 4 = ax + 7 - 3x
The system is equivalent to
[11−1a−50][xy]=[−14−11]
The system has no solutions when the determinant of [11−1a−50] is 0.
det[11−1a−50]=0−(a−5)=0a=5
Therefore, the system has no solutions when a = 5.