One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 = 24$. What is the value of $b$ in this ordered pair?
One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 = 24$. What is the value of $b$ in this ordered pair?
a2 = 24 ===> a = sqrt(24)
ab4 = 48
sqrt(24) • b4 = 48
48
b4 = ––––––––
sqrt(24)
Multiply right hand side by
sqrt(24) / sqrt(24) which is
simply multiplying it by one. 48 sqrt(24)
b4 = –––––––– • ––––––––
sqrt(24) sqrt(24)
48 • sqrt(24)
b4 = ––––––––––––
24
b4 = 2 • sqrt(24)
b4 = sqrt(96)
b4 = 961/2
b = (961/2)1/4
b = 961/8
From root function on scientific calculator b = 1.769228
.
One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 = 24$. What is the value of $b$ in this ordered pair?
a2 = 24 ===> a = sqrt(24)
ab4 = 48
sqrt(24) • b4 = 48
48
b4 = ––––––––
sqrt(24)
Multiply right hand side by
sqrt(24) / sqrt(24) which is
simply multiplying it by one. 48 sqrt(24)
b4 = –––––––– • ––––––––
sqrt(24) sqrt(24)
48 • sqrt(24)
b4 = ––––––––––––
24
b4 = 2 • sqrt(24)
b4 = sqrt(96)
b4 = 961/2
b = (961/2)1/4
b = 961/8
From root function on scientific calculator b = 1.769228
.