Find the value of $a$ so that the system has no solutions.
y = 11x+14
2y-4 = ax +5y+3
If the slopes are the same then there are no solutions because theya re parallel and do not cross
Arrange each into y = mx+ b form where m = slope find the value of 'a' that make them the same slope
the first equation is already in y = mx + b form m = 11
2y-4 = ax +5y+3
3y = -ax -7
y = - a/3 x - 7/3 so -a/3 = 11 solve for 'a'