For which value(s) of k does the following system have no solution?
4x - 6y = -2
kx - 9y = 3
First we want to get y to cancel out.
Equation 1 can be rewritten as 12x - 18y = -6
Equation 2 can be rewritten as 2kx - 18y = 6
Subtracting equation 2 from equation 1:
(12 - 2k)x = -12
(6-k)x = -6
If k = 6, then 0 = -6 which is false.
