+842 For a certain value of $k$, the system
\begin{align*}
x + y + 3z &= 10, \\
6x + 4y + z &= 18 - 5y - x, \\
kx + 7z &= 8 - 14y
\end{align*}
has no solutions. What is this value of $k$?
+129895 Rearrange as
x + y + 3z = 10
7x + 9y + z = 18
kx + 14y + 7z = 8
Multiply the second equation through by -3 = -21x -27y -3z = -54
Add to the first
-20x - 26y = -44 (1)
Multiply the second equation by -7 = -49x - 63y -7z = -126
Add to the third
(-49 + k)x -49y = -118 (2)
Multiply (1) by -49 and (2) by -26
980x + 1274y = 2156
-26(-49 + k)x + 1274y = 3068
To have no solution
980 = -26(-49 + k)
980 = 1274 - 26k
26k = 1274 - 980
26k = 294
k = 294 / 26 = 147 / 13
