If x - y = 12 and y^2 = 5(x - 2), what are the two possible values of x?
x - y = 12
y = x - 12
y^2 = 5(x - 2)
(x-12)^2 = 5(x - 2)
=^._.^=
Hi Guest,
Systems of Equation w/ Quadratics
y^2 = 5(x-2)
x = y + 12
y^2 = 5(y + 12 - 2)
y^2 = 5(y + 10)
y^2 = 5y + 50
Forms a quadratic: y^2 - 5y -50 = 0
Factor:
(y + 5)(y-10)
y = -5, y=10
So x = 7, x = 22
