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If x - y = 12 and y^2 = 5(x - 2), what are the two possible values of x?

 Aug 11, 2021
 #1
avatar+2205 
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x - y = 12

y = x - 12

y^2 = 5(x - 2)

(x-12)^2 = 5(x - 2)

 

=^._.^=

 Aug 11, 2021
 #2
avatar+62 
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Hi Guest,

 

Systems of Equation w/ Quadratics 

 

x - y = 12

y^2 = 5(x-2)

 

x = y + 12

 

y^2 = 5(y + 12 - 2)

 

y^2 = 5(y + 10)

 

y^2 = 5y + 50

 

Forms a quadratic: y^2 - 5y -50 = 0

 

Factor:

(y + 5)(y-10)

 

y = -5, y=10

 

So x = 7, x = 22

 Aug 11, 2021

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