Find the ordered pair that satisfies the system of equations
x + 3y = -4
3x - 7y = 36 + 5x - 2y
First we list the two equations.
\(x + 3y = -4 \) (1)
\(3x - 7y = 36 + 5x - 2y\) we must simplify the second equation to get:
\(-2x - 5y = 36\) (2)
Now we have a system of equations that looks much nicer. On to the math:
First we multiply equation(1) by -2 to get:
\(-2x - 6y = 8\) (3) We will call this equation 3 for the sake of clarity.
Next we subtract equation(3) from equation(2) to cancel out variable x.
\(-2x - 5y - (-2x - 6y) = 36 - 8\) This simplifies to:
\(y = 28\)
Now we can plug the value of \(y\) back into equation(1) to get \(x\):
\(x + 84 = -4\) Then we subtract 84 from both sides of the equation to get x:
\(x = -88\)
Now we have the ordered pair of (x,y)
\(x = -88\)
\(y = 28\)