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find the x,y, and z values for x+3y-3z=-12 3x-3y-4z=14 -5x+4y+5z=-15

 Oct 5, 2016
 #1
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0 x+19 y-10 z = -75 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Add 10 × (equation 3) to equation 2:
{-(5 x)+4 y+5 z = -15 | (equation 1)
0 x+19 y+0 z = -95 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Divide equation 2 by 19:
{-(5 x)+4 y+5 z = -15 | (equation 1)
0 x+y+0 z = -5 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Subtract 4 × (equation 2) from equation 1:
{-(5 x)+0 y+5 z = 5 | (equation 1)
0 x+y+0 z = -5 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Subtract 5 × (equation 3) from equation 1:
{-(5 x)+0 y+0 z = 15 | (equation 1)
0 x+y+0 z = -5 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Divide equation 1 by -5:
{x+0 y+0 z = -3 | (equation 1)
0 x+y+0 z = -5 | (equation 2)
0 x+0 y+z = -2 | (equation 3)
Collect results:
Answer: |x = -3                 y = -5                z = -2

 Oct 5, 2016
 #2
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 x+3y-3z=-12      (1)

3x-3y-4z=14       (2)

-5x+4y+5z=-15    (3)

 

Add (1)  and (2)

 

4x - 7z   = 2     (4)

 

Multiply (1) by 4   and (3)  by -3....this gives us

 

4x + 12y - 12z = -48

15x - 12y - 15z = 45        add these giving us

 

19x - 27z   = -3     (5)      multiplly (4) by 19   and (5)  by -4   ....this gives us.....

 

76x - 133z = 38

-76x + 108z = 12        add these

 

-25z   = 50       divide both sides by -25

 

z =  - 2    and using (4)  to find x, we have  that  4x - 7(-2)  = 2  →    4x + 14  = 2   →  4x = -12 →   x = -3

 

And using (1) to find y, we have :  -3 +3y-3(-2)=-12 →   3 + 3y  = -12   →  3y = -15  →  y  = -5

 

 

 

 

cool cool cool

 Oct 6, 2016

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