67 water barrels need to be carried by trucks and cars. 2 trucks and 5 cars can carry them all. If 3 trucks and 4 cars are used, there will be 5 barrels left. Determine how many barrels each truck and car can carry.

Guest Aug 6, 2022

#1**0 **

If we use these numbers, and do the math, then Your problem makes absolutely no sense.

If it is so that 3T + 4C leaves room for 5 more barrels, it seems to make more sense, but even en then

we come up with fractions for C, so I advice You to repost the problem with adjusted numbers.

Original numbers:

Water barrels:just numbers, Trucks: T, Cars: C

67 = 2T + 5C

67 - 5 = 3T + 5C, or 67 = 3T + 5C +5

Setting the first line equal to the second:

2T + 5C = 3T + 5C + 5, we subtract 5C on both sides, eliminiating C, and get

2T = 3T + 5, or T = -5 :: This makes absolutely NO sense.

Put this into the topmost line:

67 = -10 + 5C, 77 = 5C, C = 77/5 :: Also makes NO sense.

Adjusted numbers:

67 = 2T + 5C

67 + 5 = 3T + 5C, or 67 = 3T + 5C -5

2T + 5C = 3T + 5C - 5

2T = 3T - 5, or T = 5

Put into topmost:

67 = 10 + 5C, 5C = 57, and so C = 11 2/5 :: Also makes no sense.

tuffla2022 Aug 6, 2022