$${{\mathtt{t}}}^{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)} = {\frac{{\mathtt{20}}}{{\mathtt{3}}}}$$
$${\frac{{\mathtt{1}}}{{\sqrt[{{\mathtt{3}}}]{{{\mathtt{t}}}^{{\mathtt{2}}}}}}} = {\frac{{\mathtt{20}}}{{\mathtt{3}}}}$$
$${\frac{{\mathtt{3}}}{{\mathtt{20}}}} = {\sqrt[{{\mathtt{3}}}]{{{\mathtt{t}}}^{{\mathtt{2}}}}}$$
$${\frac{{\mathtt{27}}}{{\mathtt{8\,000}}}} = {{\mathtt{t}}}^{{\mathtt{2}}}$$
$${\mathtt{t}} = {\sqrt{{\frac{{\mathtt{27}}}{{\mathtt{8\,000}}}}}}$$
this correct? or do I have to do it in a different way to find out what "t" is?
