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t(20)=16e^-0.034^x

 Jun 1, 2014

Best Answer 

 #1
avatar+130511 
+5

This looks like some sort of "decay" function, so I'm going to assume you might mean.........

t(20)=16e^(-0.034x)

So, we're just putting "20" into the function to get an evaluation

So we have

$${\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\mathtt{0.034}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)} = {\mathtt{8.105\: \!871\: \!877\: \!849\: \!435\: \!2}}$$

 Jun 1, 2014
 #1
avatar+130511 
+5
Best Answer

This looks like some sort of "decay" function, so I'm going to assume you might mean.........

t(20)=16e^(-0.034x)

So, we're just putting "20" into the function to get an evaluation

So we have

$${\mathtt{16}}{\mathtt{\,\times\,}}{{\mathtt{e}}}^{{\mathtt{\,-\,}}\left({\mathtt{0.034}}{\mathtt{\,\times\,}}{\mathtt{20}}\right)} = {\mathtt{8.105\: \!871\: \!877\: \!849\: \!435\: \!2}}$$

CPhill Jun 1, 2014

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