$$\\tan^2x=\frac{4}{8}\\\\ tan^2x=\frac{1}{2}\\\\ tanx=\frac{1}{\sqrt2}\\\\ x=45\pm 180k\;\;degrees \quad k\in Z \qquad $(k is in the set of integers)$$$
$$\\tan^2x=\frac{4}{8}\\\\ tan^2x=\frac{1}{2}\\\\ tanx=\frac{1}{\sqrt2}\\\\ x=45\pm 180k\;\;degrees \quad k\in Z \qquad $(k is in the set of integers)$$$
