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if i have a right triangle how do i solve for one of the angles when i am giving the opposite and the adjacent to it?

Guest Mar 7, 2017
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\(\tan(\text{ the angle }) = \frac{ (\text{ length of side opposite the angle })}{(\text{ length of side adjacent the angle })}\)

 

Just plug in the information that you have and solve for whatever you need.

The reverse of tan is arctan. (This can also be expressed as atan or tan-1.)

 

\(( \text{ the angle }) = \arctan(\frac{ (\text{ length of side opposite the angle })}{(\text{ length of side adjacent the angle })})\)

 

The reverse of sin is arcsin (or asin or sin-1).

The reverse of cos is arccos (or acos or cos-1).

Another thing to remember is that the adjacent side can never be the hypotenuse.

hectictar  Mar 7, 2017

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