Points A and B are on a circle centered at O, and point P is outside the circle such that PA and PB are tangent to the circle. If angle OPA = 30 degrees, then what is the measure of minor arc AB, in degrees?
+130020 Connect AO, BO , PO
Tangents drawn from a single point outside a circle are equal
OP = OP
AO = BO
AP = BP
So by SSS.....triangles APO and BPO are congruent
Then because angle OPA = 30° then angle APB = 60°
And angle AOB is supplemental to angle APB = 120°
And central angle APB = measure of minor arc AB = 120°
