Team Heights

$\text{Split the team up into 2 subteams by height}\\ \text{The tallest 5 is one subteam, the shortest 5 the other}\\ \text{Any member of the tall team can stand in the back}\\ \text{Any member of the short team can stand in front}\\ \text{There are }5! \text{ ways for the 5 tall team members to arrange themselves}\\ \text{There are also }5! \text{ arrangements for the short team members}\\ \text{Thus there are }5! \times 5! = 120^2 = 14400 \text{ different arrangements}$