Find \( \frac{2^2}{2^2-1} \cdot \frac{3^2}{3^2-1} \cdot \frac{4^2}{4^2-1} \cdot \dots \cdot \frac{2006^2}{2006^2-1}. \)
∏[n^2 / (n^2 - 1), n, 2, 2006] = 1.999003488
