tell me please

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find the integral of ∫ 8e^(x+1) dx ?

gonaaa May 1, 2020

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1⁺⁰ Answers

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∫ 8 e^{x+ 1} dx =

8 ∫ e^{x + 1} dx =

8 * ( derivative of x + 1) * e^x+1 + C =

8 * ( 1) * e^x+1 + C =

8e^x+1 + C

CPhill May 1, 2020

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