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find the integral of ∫ 8e^(x+1) dx ?

 May 1, 2020
 #1
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∫ 8 ex+ 1  dx  =

 

8 ∫ ex + 1  dx  =

 

8 *  ( derivative  of x + 1) * ex+1  +  C   =

 

8 * ( 1) * ex+1  +  C  =

 

8ex+1  + C

 

cool cool cool

 May 1, 2020

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