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Ten standard 6-sided dice are rolled. What is the probability that exactly one of the dice shows a 1? Express your answer as a decimal rounded to the nearest thousandth.

Guest Dec 11, 2017
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The probability of rolling a 1 is 1/6.

The probability of rolling anything but a 1 is 5/6.

You want one 1 and nine not 1s:  (1/6) x (5/6)9.

Since there are ten different places the 1 could be rolled, you need to multiply the answer in the above line by10.

Therefore, the probability of exactly one die, out of ten, shows a 1 is:  10 x (1/6) x (5/6)9  =  10 x 1 953 125 / 60 466 176

     =  19 531 250 / 60 466 176

     =  0.323  (approximately)

geno3141  Dec 11, 2017

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