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# terminatedecimal

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113
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+1227

What is the sum of the digits in the terminating decimal representation of the fraction $$\frac{4321}{5^7\cdot2^8}$$ ?

tertre  Mar 14, 2017

#1
+5

4321/[5^7.2^8] = 0.00021605, so the sum of the digits:

2+1+6+5 =14.

Guest Mar 14, 2017
Sort:

#1
+5

4321/[5^7.2^8] = 0.00021605, so the sum of the digits:

2+1+6+5 =14.

Guest Mar 14, 2017
#2
+79894
+5

(4321)/ (5^7 * 2^8)  =  0.00021605

I'll let you do the math......

CPhill  Mar 14, 2017

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