so I don#t know how to find the zero from the factorised form of a quadratic (or things like that) when the factor contains a variable with power.
So for instance how and what would be the zero of (x-2)(x^2-x-12)=0
Thanks beforehand!
Solve for x:
(x-2) (x^2-x-12) = 0
Split into two equations:
x-2 = 0 or x^2-x-12 = 0
Add 2 to both sides:
x = 2 or x^2-x-12 = 0
The left hand side factors into a product with two terms:
x = 2 or (x-4) (x+3) = 0
Split into two equations:
x = 2 or x-4 = 0 or x+3 = 0
Add 4 to both sides:
x = 2 or x = 4 or x+3 = 0
Subtract 3 from both sides:
Answer: |
| x = 2 or x = 4 or x = -3
Solve for x:
(x-2) (x^2-x-12) = 0
Split into two equations:
x-2 = 0 or x^2-x-12 = 0
Add 2 to both sides:
x = 2 or x^2-x-12 = 0
The left hand side factors into a product with two terms:
x = 2 or (x-4) (x+3) = 0
Split into two equations:
x = 2 or x-4 = 0 or x+3 = 0
Add 4 to both sides:
x = 2 or x = 4 or x+3 = 0
Subtract 3 from both sides:
Answer: |
| x = 2 or x = 4 or x = -3
