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An observer in a lighthouse 350 feet above sea level observes two ships directly offshore. The angles of depression to the ships are β = 2° and θ = 5.5° (see figure). How far apart are the ships? (Round your answer to one decimal place.)

Guest Jan 11, 2018
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 #1
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6387.8

Guest Jan 11, 2018
 #2
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We  have this  :

 

350 / tan (2°)  -  350 / tan (5.5°)  =  distance   =  6387.8 ft

 

 

cool cool cool

CPhill  Jan 11, 2018

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