tg a/2 = 1/√3 . What is sin a ?

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Guest Sep 9, 2014

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If tan(a/2) = 1/√3 then sin(a/2) = 1/2 and cos(a/2) = (√3)/2

sin(a) = 2*sin(a/2)*cos(a/2) = 2*1/2*(√3)/2 = (√3)/2

Alan Sep 9, 2014

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Guest Sep 10, 2014

Alan · Answer 1 · 2014-09-09T06:35:59

If tan(a/2) = 1/√3 then sin(a/2) = 1/2 and cos(a/2) = (√3)/2

sin(a) = 2*sin(a/2)*cos(a/2) = 2*1/2*(√3)/2 = (√3)/2