+36 1.) What is the length of a rectangle with width 20 in. and area 148 in.6^2? The length is__in. 2) The scale of a map is 1 cm : 70 km. What is the actual distance between two towns that are 3 cm apart on the map 3.) A used-car dealership buys a car for $2900 and then sells it for $4500. What is the percent increase? The percent of increase is about__% (Round to the nearest whole number as needed)
Do you guys get paid to answer all these questions? xD or is it outta fun and competion?
+129852 1) If the area is 148 sq in., and the width is 20 in., we need to divide 148 by 20 to find the length...so we have
148/20 = 7.4 in
2) If 1cm = 70K then 3cm would be 3*70 = 210K
3) To find the % increase use
(New - Old) / Old = (4500-2900) / 2900 = about 55%
No....we don't get paid.....but donations ARE accepted......let me give you my address so you can send your check there.....!!!! (just kidding.....)
+576 2) We already know that 1 cm = 70 km in this scale. Three times as many centimeters would mean three times as many kilometers so 3cm=210 KM
+129852 1) If the area is 148 sq in., and the width is 20 in., we need to divide 148 by 20 to find the length...so we have
148/20 = 7.4 in
2) If 1cm = 70K then 3cm would be 3*70 = 210K
3) To find the % increase use
(New - Old) / Old = (4500-2900) / 2900 = about 55%
No....we don't get paid.....but donations ARE accepted......let me give you my address so you can send your check there.....!!!! (just kidding.....)
+576 3) an increase from 2900 to 4500 is an increase of 1600. 1600/2900=.55 (rounded to nearest hundredth) so this is about a 55% increase
+576 Of course we get paid! Our currency is math problems and we get them upfront. Thanks for the three that you just donated!
+11912 Hmmmn!thats right jboy and Melody is the richest of us!shes a millionaire!
