+0  
 
0
67
1
avatar+464 

Thank you in advance for helping me solve this. Can I please get it today before 6:30 pm if possible please!

 

shreyas1  Oct 8, 2018
 #1
avatar+92463 
+1

AWX  and AYZ  are under the same height

So....they are to each other as teir bases

So  WX / YZ  =  30/20   = 3/2

WX =  (3/2)YZ

 

So

 

WX + XY   = 9    ⇒  (3/2)YZ + XY  = 9       (1)

XY + YZ  =  7     ⇒  YZ + XY  =  7         (2)

 

Subtract  (2)  from (1)  and we have that

 

(1/2)YZ  = 2

YZ  = 4

So XY = 3

And WX = (3/2)YZ  = (3/2)4  = 6

 

So......the height of   AWX  can be found as

 

30  = (1/2) WX * height

30  = 3 * height

10 =  height  of  AWX  = height of  AXY

 

So...the area of AXY  =  (1/2)XY * 10  =  (1/2)(3)(10) =  15 units^2

 

cool cool cool

CPhill  Oct 8, 2018

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