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AWX  and AYZ  are under the same height

So....they are to each other as teir bases

So  WX / YZ  =  30/20   = 3/2

WX =  (3/2)YZ

So

WX + XY   = 9    ⇒  (3/2)YZ + XY  = 9       (1)

XY + YZ  =  7     ⇒  YZ + XY  =  7         (2)

Subtract  (2)  from (1)  and we have that

(1/2)YZ  = 2

YZ  = 4

So XY = 3

And WX = (3/2)YZ  = (3/2)4  = 6

So......the height of   AWX  can be found as

30  = (1/2) WX * height

30  = 3 * height

10 =  height  of  AWX  = height of  AXY

So...the area of AXY  =  (1/2)XY * 10  =  (1/2)(3)(10) =  15 units^2