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THANKS CPHILLLLLLL!!!!! I need help!!

 △ABC∼△EFG ​.

 

Given m∠B=48° and m∠G=61° , what is m∠A ?

 

Enter your answer in the box.

 Jan 5, 2018

Best Answer 

 #1
avatar+8437 
+2

Since   △ABC ∼ △EFG ,    m∠C  =  m∠G  .

 

Since   m∠G  =  61°  ,   m∠C  =  61°

 

Now we know two of the angles in triangle  ABC  ....

 

m∠B  =  48°   and   m∠C  =  61°  .

 

How can we find the measure of the third angle, angle A ?

 

Remember that the sum of the angles in every triangle  =  180°

 

m∠A  +  m∠B  +  m∠C   =   180°      Plug in what we know....

 

m∠A  +   48°   +    61°    =   180°     Subtract  61°  and  48°  from both sides of the equation.

 

m∠A   =   180°  -  61°  -  48°

 

m∠A   =   71°

 Jan 5, 2018
 #1
avatar+8437 
+2
Best Answer

Since   △ABC ∼ △EFG ,    m∠C  =  m∠G  .

 

Since   m∠G  =  61°  ,   m∠C  =  61°

 

Now we know two of the angles in triangle  ABC  ....

 

m∠B  =  48°   and   m∠C  =  61°  .

 

How can we find the measure of the third angle, angle A ?

 

Remember that the sum of the angles in every triangle  =  180°

 

m∠A  +  m∠B  +  m∠C   =   180°      Plug in what we know....

 

m∠A  +   48°   +    61°    =   180°     Subtract  61°  and  48°  from both sides of the equation.

 

m∠A   =   180°  -  61°  -  48°

 

m∠A   =   71°

hectictar Jan 5, 2018

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