What is the remainder when the polynomial \(g(x) = x^3-14x^2+18x+72\)
is divided by \(x-1\)
By doing the long division:
x^2 - 13x -5 R 77
(x-1) | x^3 -14x^2 +18x +72
x^3 -x^2
-13x^2 + 8x
-13x^2 +13x
-5x + 72
-5x + 5
77
Thx, EP.....we can also apply the Remainder Theorem
If a polynomial P(x) is divded by x - a , the remainder = P(a)
So....letting a = 1 , we have
1^3 - 14(1)^2 + 18(1) + 72 =
1 - 14 + 90
91 - 14 =
77 just as EP found !!!
We can see the logic of this....if x =1 were a root....then P(1) = 0