+0  
 
0
250
1
avatar+644 

Give an example of a quadratic function that has zeroes at x=2 and x=4, and that takes the value 6 when x=3. Enter your answer in the expanded form "ax^2 + bx + c", where a,b,c are replaced by appropriate numbers.

waffles  Oct 22, 2017
 #1
avatar+92788 
+3

 

P (x) = a (x - 2) (x - 4)     and we need to find "a"

 

And when x =  3  we have that 

 

 a( 3 - 2) (3 - 4)  = 6    simplify   and solve for "a"

 

a (-1) = 6  →   a =  -6

 

So we have

 

-6 [ x^2 - 6x + 8]  =

 

P(x) =  -6x^2 + 36x - 48

 

 

cool cool cool

CPhill  Oct 22, 2017

11 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.