The ages of members of a bowling league are normally distributed with a mean of 43 years and a standard deviation of 4 years.
There are 200 members in the league.
About how many members are expected to be between 35 years old and 51 years old?
35 is 2 standard deviations BELOW the mean of 43
51 is 2 standard deviations ABOVE the mean of 43
find z - score for + 2 S.D. then subtract the z-score for - 2 S.D.
This is the percentage ( in decimal form) of 200 members between the ages of 35 and 51 Can you finish?