The altitude of an equilateral triangle is sq. root 6 units. What is the area of the triangle, in square units? Express your answer in simplest radical form.
The altitude in such a triangle will result in a half-base that is (1/ √3) as long as the altitude....
So this half-base = √6 / √3 = √2
So...the area of this triangle = √2 * √6 = √12 = √[4 *3] = 2√3 sq. units
+1314 
