#2**0 **

Here's an explanation...

Let's find sin θ using the Pythagorean identity.

sin^{2}θ + cos^{2}θ = 1

sin^{2}θ + (3/5)^{2} = 1

sin^{2}θ = 1 - (3/5)^{2} sin is positive in Quad I , so take the positive sqrt of both sides.

sin θ = √[ 1 - (3/5)^{2} ]

sin θ = 4/5

And...

tan θ = sin θ / cos θ = (4/5) / (3/5) = 4/3

hectictar Dec 6, 2017