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The angle θ lies in Quadrant I.

 

cosθ=3/5

What is tanθ?

 

−4/3

4/3

4/5

−4/5

 Dec 6, 2017
 #1
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4/3     

 Dec 6, 2017
 #2
avatar+7612 
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Here's an explanation...

 

Let's find  sin θ  using the Pythagorean identity.

 

sin2θ  +  cos2θ   =   1

 

sin2θ  +  (3/5)2   =   1

 

sin2θ   =   1 - (3/5)2      sin is positive in Quad I , so take the positive sqrt of both sides.

 

sin θ   =   √[ 1 - (3/5)2 ]

 

sin θ   =   4/5

 

And...

 

tan θ   =   sin θ / cos θ   =   (4/5) / (3/5)   =   4/3

 Dec 6, 2017

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