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Find the inradius of triangle JKL if JK=JL=17 and KL=16

 Oct 28, 2018
 #1
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This is what I got!!

 

side length | 17
circumradius | 289/30≈9.63333
inradius | 24/5 = 4.8
width | 16
height | 15
area | 120
perimeter | 50
interior angles | ((180 cos^(-1)(8/17))/π° | (180 cos^(-1)(8/17))/π° | (180 cos^(-1)(161/289))/π°)≈(1.081 rad | 1.081 rad | 0.9799 rad)
interior angle sum | 180° = π rad≈3.142 rad
exterior angle sum | 360° = 2 π rad≈6.283 rad

 Oct 28, 2018

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