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The area of a playground is 320 yd2. The width of the playground is 4 yd longer than its length. Find the length and width of the playground.

 Feb 17, 2015

Best Answer 

 #1
avatar+130514 
+5

W = L + 4   ...so......

(L)(L + 4) = 320  simplify

L^2 + 4L - 320 = 0      factor

(L - 16) (L + 20) = 0       and setting each factor to 0, we have that x = 16 or x = -20

Reject the negative

So,  L = 16   and W = L + 4 = 20

 

 Feb 17, 2015
 #1
avatar+130514 
+5
Best Answer

W = L + 4   ...so......

(L)(L + 4) = 320  simplify

L^2 + 4L - 320 = 0      factor

(L - 16) (L + 20) = 0       and setting each factor to 0, we have that x = 16 or x = -20

Reject the negative

So,  L = 16   and W = L + 4 = 20

 

CPhill Feb 17, 2015

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