The area of a square is represented by x2-30x+225. What is the perimeter of the square?

The sides are  x-15

So the perimeter is  4x-60 units

{nl} ${x}^{2}-30x+225$ right?

your square, by defenition, has equal length sides;

area = the length of one side squared

perimiter = the length of one side times 4

therefore the conversion from area to perimiter is;

     square root and times by 4

try quadratic factorising;

first we need some information;

     - the signs are negative and positive and therefore both signs must be negative in the brackets

     - $\sqrt{225}=15$

     - the question has given you the area in a 'quadraticy' way - it is likley therefore that factorising it will work

then do it!

$(x-15)(x-15)$

as;

$side length\times sidelength = (x-15)(x-15)$

we can conclude that the length of one side is $x-15$.

Next we need to find the perimiter - which is the sidelength times 4

$(x-15)\times4$

$4x - 60$ = perimiter

hope this helps