The area of the base of a cube is twice the area of the base of a second cube. What is the ratio of their volumes.

Thank you! :)

If the area of the base of one cube is twice that of the other, the ratio of their sides is s√2 to s

So, the ratio of their volumes is  (s√2)^3 / s^3  = (√2)^3  = 2√2