The area of this isosceles triangle is 8cm^{2}.

The angle ABC is 27^{o}.

Work out the length of x.

Give the answer to 1 d.p. or better.

We can find x as follows :

Area = (1/2) * x^2 * sin(27°)

8 = (1/2) * x^2 * sin(27°) multiply both sides by 2

16 = x^2 * sin (27°) divide both sides by sin (27°)

[ 16 / sin (27°) ] = x^2 take the square root of both sides

sqrt [ 16 / sin (27°) ] = x ≈ 5.937 cm^2