The base of the triangle is 8cm less than the height. If the area of the triangle is at least 60 cm squared which inequality represents the

Let the base be representd by h-8

And the area is given by  b*h /2 = (h-8)*h / 2

And this is "at least" 60cm² ....and "at least" is analogous to "≥" ... so we have...

(h-8)*h / 2  ≥  60 cm²   .... which we could also express as....

h² - 8h  ≥ 120 cm²