The boat is going 10 miles per hour in still water it takes 2 hours to go downstream and 3 hours to go upstream. What’s the speed of the current and distance of the trip?
+128460 Let C be the rate of the current
Downstream the rate of the boat = 10 + C
Upstream the rate = 10 - C
So rate * time = distance.....so equating distances we have that
(10+C ) * 2 = (10 - C) * 3 (1)
20 + 2C = 30 - 3C rearrange as
5C = 10 divide both sides by 5
C = 2 [ the speed of the current = 2 mph ]
And using either side of (1).....the distance is 2 (10 + 2) = 24 miles
