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The book is mistaken

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Ok, so we got this question in the math book, but every time we try and solve it the equation doesn't balence. We've put it through the calculator and the mind of google itself and it doesn't balence either. Can anyone give us an answer?

Š(x^3+3x^2-8)-x-1=0

I assume the book is just wrong, and that it doesn't balence in the end, but I would like to check with some good minds, just in case.
 Nov 5, 2013

5+0 Answers

 #1
avatar+118654 
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Š(x^3+3x^2-8)-x-1=0

What is S?
 Nov 5, 2013
 #2
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It's the symbol the calculator made when I copied over the cubed root symbol.
 Nov 5, 2013
 #3
avatar+118654 
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cubed root of [(x^3+3x^2-8)-x-1]=0
A cubed root is a power of 1/3

[(x^3+3x^2-8)-x-1] 1/3 = 0

Raise both sides to the power of 3

{[(x^3+3x^2-8)-x-1] 1/3} 3 = 0 3

(x^3+3x^2-8)-x-1= 0

x^3+3x^2-8-x-1= 0

x^3+3x^2-x-9= 0

I can't do this, I think one of the digits is wrong. Are you sure you copied the question correctly?
 Nov 5, 2013
 #4
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I pretty sure that is a solvable problem, but I don't have time to it now.

Will get back to you later.
 Nov 6, 2013
 #5
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@Melody - Yeah, the problem is put exactly as it is in the book. Thanks for giving it a shot though.

@Kytuzian - I'd appreciate it. ^_^
 Nov 6, 2013

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