The closed form sum of 12[1^2*2+2^2*3+...+n^2(n+1)] for n>=1 is n(n+1)(n+2)(an+b). Find an+b.
"The closed form sum of 12[1^2*2+2^2*3+...+n^2(n+1)] for n>=1 is n(n+1)(n+2)(an+b). Find a and b."
.
But what is n?
n is an unspecified positive integer. If you want a single numerical result for the sum you must specify the value for n.
For example:
n = 5 means n(n+1)(n+2)(3n+1) = 3360
n=9 means n(n+1)(n+2)(3n+1) = 27720
etc.
The sum is a function of n.
