This is known as an "indeterminate" form.....to see why.......note
0^0 = 0^(n - n) = 0^n / 0^n....but 0^n = 0
So we have 0 / 0......which implies that anything multiplied by the denominator = the numerator.....but "anything" is not a definite quantity......thus.....it's indeterminate....