+130511 Anonymous's answer can be seen clearly by the following diagram......
Point "A" could only have a symmetric point about a diagonal whose slope was 1. (In other words, the point (8, -2) would have to lie on the rectangle.....it doesn't). But diagonal BC has a slope of 1/4. And point "B" could only have a symmetric point about a diagonal whose slope was -1. (Point (-2,-8) would have to lie on the rectangle...it doesn't either). But diagonal AD has a slope of -1/4.
The axes of symmetry are the x axis and the y axis.
The answer is false because if you tried to fold a rectangle in half diagonally, it would not match up. A square however, would.
+130511 Anonymous's answer can be seen clearly by the following diagram......
Point "A" could only have a symmetric point about a diagonal whose slope was 1. (In other words, the point (8, -2) would have to lie on the rectangle.....it doesn't). But diagonal BC has a slope of 1/4. And point "B" could only have a symmetric point about a diagonal whose slope was -1. (Point (-2,-8) would have to lie on the rectangle...it doesn't either). But diagonal AD has a slope of -1/4.
The axes of symmetry are the x axis and the y axis.
