The difference of the roots of the quadratic equation $x^2 + bx + c = 0$ is $|b - 2c|$. If $c \neq 0$, then find $c$ in terms of $b$.

By the quadratic formula, c = b + 4.

so what is the answer

\(\text{By } x = {-b \pm \sqrt{b^2-4ac} \over 2a}, c = b+4\)