The directrix of a parabola is x = 0. Its focus is (2,6) .
What is the standard form of the parabola?
vertex is directly between the focus (2,6) and directrix x=0
so vertex is 1,6
this parabola opens to the right..... can that get you started?
could u please solve it if possible?
It is in the graph link I supplied....did you look at it?
Vertex form of this parabola x = a (y-k)^2 + h
Here is a graph if you are stuck.....