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The directrix of a parabola is x = 0. Its focus is (2,6) .

What is the standard form of the parabola?

 Jan 3, 2020
 #1
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vertex is directly between the focus (2,6) and directrix x=0

   so   vertex is  1,6

this parabola opens to the right.....     can that get you started?

 Jan 4, 2020
 #3
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could u please solve it if possible?

Beanpole  Jan 4, 2020
 #4
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It is in the graph link I supplied....did you look at it?

 

Vertex form of this parabola       x = a (y-k)^2 + h      

ElectricPavlov  Jan 4, 2020
 #2
avatar+19815 
0

Here is a graph if you are stuck.....

 

https://www.desmos.com/calculator/94brhqodjk

 Jan 4, 2020

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